Systems of Equations
Solve two linear equations by elimination — every step explained, with exact fraction answers.
x+y=
x+y=
- 1
The system of equations.
2x + 3y = 12
x − y = 1
- 2
Line up the y-terms: multiply equation 1 by b₂ and equation 2 by b₁.
-2x − 3y = -12
3x − 3y = 3
- 3
Subtract the equations to eliminate y, then solve for x.
-5x = -15
x = 3
- 4
Substitute x back in to find y.
2x + 3y = 12 with x = 3
y = 2
Solution
x = 3, y = 2